$\dfrac{11}{23}\times\dfrac{3}{2}$ =

$\dfrac{15}{3}\times\dfrac{11}{6}$ =

$2 \times\dfrac{13}{13}$ =

$\dfrac{3}{14}\times\dfrac{11}{4}$ =

$\dfrac{5}{10}\times\dfrac{13}{21}$ =

$\dfrac{9}{6}\times\dfrac{11}{23}$ =

$\dfrac{3}{50}\times 7$ =

$\dfrac{2}{-33}\times\dfrac{-2}{3}$ =

$\dfrac{5}{6}\times\dfrac{11}{2}$ =

$4 \times\dfrac{10}{-20}$ =