$\dfrac{3}{34}\times 5$ =

$\dfrac{7}{2}\times\dfrac{7}{3}$ =

$\dfrac{2}{3}\times\dfrac{17}{3}$ =

$\dfrac{2}{-7}\times\dfrac{6}{-11}$ =

$\dfrac{3}{11}\times\dfrac{6}{15}$ =

$3 \times\dfrac{-15}{9}$ =

$15 \times\dfrac{5}{15}$ =

$\dfrac{3}{17}\times\dfrac{15}{10}$ =

$\dfrac{7}{5}\times\dfrac{7}{12}$ =

$\dfrac{19}{7}\times\dfrac{10}{35}$ =