$\,2 +\,4\times(\,-3\,x\,) \,-3 =$ ?

$\,-12\,x +\,5$ $\,-18\,x \,-3$ $\,12\,x \,-1$ $\,x \,-1$ $\,-12\,x \,-1$

$\,2\times \,x \times \,4 + \,x \times (\,-3\,x\,) =$ ?

$\,5\,\,x^2$ $\,-3\,\,x^2 +\,8\,x$ $\,-3\,\,x^2 +\,6\,x$ $\,3\,\,x^2 +\,8\,x$ $\,-3\,\,x^2 \,-8\,x$

$\,-8\,y \times (\,-9\,x\,) +\,6\,xy =$ ?

$\,66\,xy$ $\,-8\,y \,-9\,x +\,6\,xy$ $\,-11\,xy$ $\,78\,xy$ $\,-66\,xy$

$\,4 +\,2\,x \,-5\,y +\,5\,x +\,7=$ ?

$\,7\,x \,-5\,y +\,11$ $\,7\,x \,-5\,y \,-3$ $\,2\,xy +\,11$ $\,-3\,x \,-5\,y +\,11$ $\,11\,x \,-5\,y +\,7$

$\,-2\,x \,-7 \,-8\,x \,-3 \,-7\,x=$ ?

$\,-17\,x \,-10$ $\,-21\,x$ $\,-17\,x +\,4$ $\,-3\,x \,-10$ $\,-\,x +\,4$ $\,-27\,x$

$\,8\,x \,-6\,y \,-7\,y \,-2\,x=$ ?

$\,10\,x \,-13\,y$ $\,2\,xy \,-9\,yx$ $\,6\,x \,-13\,y$ $\,6\,x \,-\,y$ $\,10\,x +\,y$

$\,6\,x \,-4 \,-9\,x =$ ?

$\,6\,x \,-13\,x$ $\,15\,x \,-4$ $\,-3\,x \,-4$ $\,-15\,x \,-4$ $\,-7\,x$

$\,8\,x +\,6\,\,x^2 \,-9 \,-8\,\,x^2 \,-7=$ ?

$\,-16\,\,x^2 +\,8\,x \,-2$ $\,14\,\,x^2 +\,8\,x \,-16$ $\,6\,\,x^2 \,-16$ $\,-14\,\,x^2 +\,8\,x +\,2$ $\,-2\,\,x^2 +\,8\,x \,-16$