$\dfrac{3}{44}\times 5$ =

$\dfrac{-10}{11}\times\dfrac{-5}{7}$ =

$\dfrac{4}{3}\times\dfrac{2}{33}$ =

$\dfrac{6}{7}\times\dfrac{10}{35}$ =

$\dfrac{4}{7}\times\dfrac{3}{14}$ =

$\dfrac{15}{20}\times\dfrac{7}{10}$ =

$11 \times\dfrac{25}{-55}$ =

$\dfrac{3}{2}\times\dfrac{3}{5}$ =

$15 \times\dfrac{13}{39}$ =

$\dfrac{3}{5}\times\dfrac{3}{10}$ =