$\dfrac{3}{2}\times\dfrac{3}{11}$ =

$\dfrac{3}{6}\times\dfrac{23}{17}$ =

$\dfrac{3}{4}\times\dfrac{6}{23}$ =

$\dfrac{7}{2}\times\dfrac{3}{23}$ =

$13 \times\dfrac{-6}{26}$ =

$\dfrac{-3}{19}\times\dfrac{-3}{2}$ =

$\dfrac{2}{27}\times 13$ =

$5 \times\dfrac{15}{15}$ =

$\dfrac{10}{6}\times\dfrac{10}{33}$ =

$\dfrac{14}{11}\times\dfrac{2}{3}$ =