$\dfrac{7}{5}\times\dfrac{2}{11}$ =

$\dfrac{2}{14}\times\dfrac{23}{4}$ =

$\dfrac{2}{3}\times\dfrac{2}{13}$ =

$\dfrac{19}{9}\times\dfrac{6}{5}$ =

$17 \times\dfrac{3}{17}$ =

$\dfrac{2}{-3}\times\dfrac{5}{-13}$ =

$2 \times\dfrac{-10}{4}$ =

$\dfrac{7}{19}\times\dfrac{3}{2}$ =

$\dfrac{4}{7}\times\dfrac{8}{14}$ =

$\dfrac{3}{49}\times 13$ =