$\dfrac{7}{18}\times 7$ =

$\dfrac{6}{11}\times\dfrac{4}{15}$ =

$\dfrac{2}{13}\times\dfrac{7}{3}$ =

$\dfrac{7}{5}\times\dfrac{7}{11}$ =

$\dfrac{3}{-2}\times\dfrac{7}{-19}$ =

$\dfrac{25}{11}\times\dfrac{2}{3}$ =

$\dfrac{13}{25}\times\dfrac{10}{11}$ =

$-5 \times\dfrac{9}{15}$ =

$\dfrac{5}{3}\times\dfrac{25}{10}$ =

$7 \times\dfrac{14}{49}$ =