$\dfrac{3}{13}\times\dfrac{33}{2}$ =

$17 \times\dfrac{3}{17}$ =

$\dfrac{9}{5}\times\dfrac{11}{6}$ =

$\dfrac{7}{6}\times\dfrac{14}{4}$ =

$\dfrac{19}{17}\times\dfrac{1}{2}$ =

$\dfrac{3}{34}\times 5$ =

$2 \times\dfrac{19}{-19}$ =

$\dfrac{3}{7}\times\dfrac{3}{11}$ =

$\dfrac{7}{-19}\times\dfrac{-3}{2}$ =

$\dfrac{23}{9}\times\dfrac{2}{4}$ =