$\dfrac{23}{11}\times\dfrac{5}{40}$ =

$\dfrac{2}{33}\times\dfrac{10}{3}$ =

$\dfrac{7}{33}\times 2$ =

$23 \times\dfrac{5}{-23}$ =

$15 \times\dfrac{5}{15}$ =

$\dfrac{-3}{5}\times\dfrac{3}{-10}$ =

$\dfrac{11}{10}\times\dfrac{35}{5}$ =

$\dfrac{7}{10}\times\dfrac{25}{3}$ =

$\dfrac{2}{3}\times\dfrac{2}{7}$ =

$\dfrac{3}{23}\times\dfrac{13}{2}$ =