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QUIZ
Réduire une expression sans parenthèses (QCM)
Question 1 :
$\,-8 +\,6\times\,5\,x \,-2 =$ ?
$\,11\,x \,-10$ $\,30\,x \,-10$ $\,-30\,x \,-10$ $\,-10\,x \,-2$ $\,30\,x \,-6$
Question 2 :
$\,-8\,x \,-4\,\,x^2 +\,4 \,-9\,\,x^2 +\,9=$ ?
$\,-21\,\,x^2 +\,13$ $\,-13\,\,x^2 \,-8\,x +\,5$ $\,13\,\,x^2 \,-8\,x \,-13$ $\,-13\,\,x^2 \,-8\,x +\,13$ $\,-5\,\,x^2 \,-8\,x +\,5$
Question 3 :
$\,9\,x \,-4 +\,8\,x =$ ?
$\,9\,x +\,4\,x$ $\,13\,x$ $\,17\,x \,-4$ $\,x \,-4$ $\,-\,x \,-4$
Question 4 :
$\,6\,y \times (\,-2\,x\,) \,-3\,xy =$ ?
$\,xy$ $\,-15\,xy$ $\,9\,xy$ $\,-9\,xy$ $\,6\,y \,-2\,x \,-3\,xy$
Question 5 :
$\,-2\,x +\,8 \,-4\,x +\,6 \,-8\,x=$ ?
$\,-6\,x \,-2$ $\,-14\,x +\,14$ $\,-14\,x \,-2$ $\,-12\,x$ $\,2\,x +\,14$
Question 6 :
$\,-9\times \,x \times (\,-3\,) + \,x \times (\,-8\,x\,) =$ ?
$\,-8\,\,x^2 \,-12\,x$ $\,-8\,\,x^2 \,-27\,x$ $\,-8\,\,x^2 +\,27\,x$ $\,19\,\,x^2$ $\,8\,\,x^2 +\,27\,x$
Question 7 :
$\,5\,x \,-9\,y \,-6\,y +\,8\,x=$ ?
$\,-4\,xy +\,2\,yx$ $\,13\,x +\,3\,y$ $\,-3\,x \,-15\,y$ $\,13\,x \,-15\,y$ $\,-3\,x \,-3\,y$
Question 8 :
$\,7 +\,7\,x +\,8\,y +\,5\,x +\,6=$ ?
$\,19\,x +\,8\,y +\,6$ $\,2\,x +\,8\,y +\,13$ $\,20\,xy +\,13$ $\,12\,x +\,8\,y +\,1$ $\,12\,x +\,8\,y +\,13$